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To prepare for the Oracle 1Z0-829 exam, candidates should have a solid understanding of Java SE 17 fundamentals and should be familiar with advanced concepts and techniques. Candidates should also have experience working with Java-based applications and should be comfortable using development tools such as Eclipse or NetBeans.
NEW QUESTION # 18
Given the code fragment:
What is the result?
- A. Logged out at: 2021-0112T21:58:19.880z
- B. Logged out at: 2021-01-12T21:58:00z
- C. Can't logout
- D. A compilation error occurs at Line n1.
Answer: B
Explanation:
Explanation
The code fragment is using the Java SE 17 API to get the current time and then truncating it to minutes. The result will be the current time truncated to minutes, which is why option B is correct. References:
https://education.oracle.com/products/trackp_OCPJSE17
https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487
https://docs.oracle.com/javase/17/docs/api/java.base/java/time/Instant.html#truncatedTo(java.time.tempora
NEW QUESTION # 19
Given the code fragment:
What is the result?
- A. Range1
Note a valid rank. - B. Range 1
- C. Range 1
Range 2
Range 3 - D. Range 1
Range 2
Range 3
Range 1
Not a valida rank
Answer: D
Explanation:
The code fragment is using the switch statement with the new Java 17 syntax. The switch statement checks the value of the variable rank and executes the corresponding case statement. In this case, the value of rank is 4, so the first case statement is executed, printing "Range1". The second and third case statements are also executed, printing "Range2" and "Range3". The default case statement is also executed, printing "Not a valid rank". Reference: Java Language Changes - Oracle Help Center
NEW QUESTION # 20
Given the product class:
And the shop class:
What is the result?
- A. An exception is produced at runtime
- B. Cookie 2.99 2.99
- C. Cookie 0.0 2.99
- D. Cookie 0.0 0.0
- E. Cookie 3.99 2.99
- F. Compilation fails
Answer: F
Explanation:
The code fragment will fail to compile because the readObject method in the Product class is missing the @Override annotation. The readObject method is a special method that is used to customize the deserialization process of an object. It must be declared as private, have no return type, and take a single parameter of type ObjectInputStream. It must also be annotated with @Override to indicate that it overrides the default behavior of the ObjectInputStream class. Without the @Override annotation, the compiler will treat the readObject method as a normal method and not as a deserialization hook. Therefore, the code fragment will produce a compilation error. Reference: Object Serialization - Oracle, [ObjectInputStream (Java SE 17 & JDK 17) - Oracle]
NEW QUESTION # 21
Given the directory structure:
Given the definition of the Doc class:
Which two are valid definition of the wordDoc class?
- A. Package p1;
Public non-sealed class wordDoc extends Doc () - B. Package p1;
Public class wordDoc extends Doc () - C. Package p1, p2;
Public non-sealed class WordDoc extends Doc () - D. Package p1;
Public final class WordDoc extends Doc () - E. Package p1,
non-sealed abstract class WordDoc extends Doc () - F. Package p1, p2;
Public sealed class WordDoc extends Doc ()
Answer: A,D
Explanation:
The correct answer is A and F because the wordDoc class must be a non-sealed class or a final class to extend the sealed Doc class. Option B is incorrect because the wordDoc class must be non-sealed or final. Option C is incorrect because the wordDoc class cannot be in a different package than the Doc class. Option D is incorrect because the wordDoc class cannot be a sealed class. Option E is incorrect because the wordDoc class cannot be an abstract class. Reference: Oracle Certified Professional: Java SE 17 Developer, 3 Sealed Classes - Oracle Help Center
NEW QUESTION # 22
Given the code fragments:
Which action prints Wagon : 200?
- A. At Line n3, replace Car with LuxurayCar.
- B. At line n3, replace readObject (0 with readLine().
- C. At Line n1, implement the java.io.AutoCloseable interface
- D. At line n2, in the main method signature, add throws IOException, ClassCastException.
- E. At line n2, in the main method signature, add throws IoException, ClassNotFoundException.
- F. At line n1, implement the java.io, Serializable interface.
Answer: E
Explanation:
Explanation
The code fragment is trying to read an object from a file using the ObjectInputStream class. This class throws an IOException and a ClassNotFoundException. To handle these exceptions, the main method signature should declare that it throws these exceptions. Otherwise, the code will not compile. If the main method throws these exceptions, the code will print Wagon : 200, which is the result of calling the toString method of the LuxuryCar object that was written to the file. References: ObjectInputStream (Java SE 17 & JDK 17) - Oracle, ObjectOutputStream (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 23
Given the code fragment:
Which action enables the code to compile?
- A. Remove the regNO initialization statement.
- B. Replace thye regNo variable static
- C. Replace record with void.
- D. Make the regNo variable static.
- E. Make the regNo variable public
Answer: E
Explanation:
Explanation
The code will compile if the regNo variable is made public. This is because the regNo variable is being accessed in the main method of the App class, which is outside the scope of the Product class. Making the regNo variable public will allow it to be accessed from outside the class. References:
https://education.oracle.com/products/trackp_OCPJSE17,
https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487,
https://docs.oracle.com/javase/tutorial/java/javaOO/accesscontrol.html
NEW QUESTION # 24
Assuming that the data, txt file exists and has the following content:
Text1
Text2
Text3
Given the code fragment:
What is the result?
- A. text1-
text2-
text3-
text3 - B. text1-text2-text3
text1
text2
text3 - C. text1-text2-text3
text3 - D. text1-text2-text3
A java.lang.indexoutofBoundsException is thrown.
Answer: C
Explanation:
Explanation
The answer is D because the code fragment reads the file "data.txt" and collects all the lines in the file into a single string, separated by hyphens. Then, it prints the resulting string. Next, it attempts to read the fourth line in the file (index 3) and print it. However, since the file only has three lines, an IndexOutOfBoundsException is thrown. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Read contents of a file using Files class in Java
NEW QUESTION # 25
Given:
and the code fragment:
- A. 300.00
CellPhone.ToyCar - B. 100.00
CellPhone,ToyCar,Motor,Fan - C. 300.00
CellPhone,ToyCar,Motor,Fan - D. 100.00 CellPhone,ToyCar
Answer: C
Explanation:
The code fragment is using the Stream API to perform a reduction operation on a list of ElectricProduct objects. The reduction operation consists of three parts: an identity value, an accumulator function, and a combiner function. The identity value is the initial value of the result, which is 0.0 in this case. The accumulator function is a BiFunction that takes two arguments: the current result and the current element of the stream, and returns a new result. In this case, the accumulator function is (a,b) -> a + b.getPrice (), which means that it adds the price of each element to the current result. The combiner function is a BinaryOperator that takes two partial results and combines them into one. In this case, the combiner function is (a,b) -> a + b, which means that it adds the two partial results together.
The code fragment then applies a filter operation on the stream, which returns a new stream that contains only the elements that match the given predicate. The predicate is p -> p.getPrice () > 10, which means that it selects only the elements that have a price greater than 10. The code fragment then applies a map operation on the filtered stream, which returns a new stream that contains the results of applying the given function to each element. The function is p -> p.getName (), which means that it returns the name of each element.
The code fragment then calls the collect method on the mapped stream, which performs a mutable reduction operation on the elements of the stream using a Collector. The Collector is Collectors.joining (","), which means that it concatenates the elements of the stream into a single String, separated by commas.
The code fragment then prints out the result of the reduction operation and the result of the collect operation, separated by a new line. The result of the reduction operation is 300.00, which is the sum of the prices of all ElectricProduct objects that have a price greater than 10. The result of the collect operation is CellPhone,ToyCar,Motor,Fan, which is the concatenation of the names of all ElectricProduct objects that have a price greater than 10.
Therefore, the output of the code fragment is:
300.00 CellPhone,ToyCar,Motor,Fan
NEW QUESTION # 26
Given the code fragment:
What is the result?
- A. Cat
Dog - B. Dog
Dog - C. A NullPointerException is thrown
Cat
Cat - D. Cat
null
Answer: D
Explanation:
The answer is E because the code fragment creates a new Pet object with the name "Dog" and assigns it to the variable p. Then, it assigns p to p1. Next, it changes the name of p1 to "Cat". Then, it assigns p1 to p. Finally, it sets p to null and prints the name of p and p1. The output will be "Cat" and "null" because p is set to null and p1 still points to the Pet object with the name "Cat".
NEW QUESTION # 27
Given the course table:
Given the code fragment:
- A. 0
- B. 1
- C. true
- D. false
Answer: C
Explanation:
Explanation
The code fragment will execute the update statement and set the course fee of the course with ID 1021 to
5000. The executeUpdate method returns an int value that indicates the number of rows affected by the SQL statement. In this case, only one row will be updated, so the result variable will be 1. The if statement will check if the result is greater than 0, which is true, and print "Updated successfully". Therefore, the output of the code fragment is true. References: https://education.oracle.com/products/trackp_OCPJSE17,
https://mylearn.oracle.com/ou/learning-path/java-se-17-developer/99487,
https://docs.oracle.com/en/java/javase/17/docs/api/java.sql/java/sql/Statement.html#executeUpdate(java.lang.Str
NEW QUESTION # 28
Given the code fragments:
Which action prints Wagon : 200?
- A. At Line n3, replace Car with LuxurayCar.
- B. At line n3, replace readObject (0 with readLine().
- C. At Line n1, implement the java.io.AutoCloseable interface
- D. At line n2, in the main method signature, add throws IOException, ClassCastException.
- E. At line n2, in the main method signature, add throws IoException, ClassNotFoundException.
- F. At line n1, implement the java.io, Serializable interface.
Answer: E
Explanation:
The code fragment is trying to read an object from a file using the ObjectInputStream class. This class throws an IOException and a ClassNotFoundException. To handle these exceptions, the main method signature should declare that it throws these exceptions. Otherwise, the code will not compile. If the main method throws these exceptions, the code will print Wagon : 200, which is the result of calling the toString method of the LuxuryCar object that was written to the file. Reference: ObjectInputStream (Java SE 17 & JDK 17) - Oracle, ObjectOutputStream (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 29
Given:
What is the result?
- A. 0
- B. Compilation fails.
- C. 1
- D. 2
- E. Nothing is printed because of an indefinite loop.
- F. 3
- G. 4
- H. A runtime exception is thrown.
Answer: B
Explanation:
The code will not compile because the variable 'x' is declared as final and then it is being modified in the switch statement. This is not allowed in Java. A final variable is a variable whose value cannot be changed once it is initialized1. The switch statement tries to assign different values to 'x' depending on the value of 'y', which violates the final modifier. The compiler will report an error: The final local variable x cannot be assigned. It must be blank and not using a compound assignment. Reference: The final Keyword (The Java™ Tutorials > Learning the Java Language > Classes and Objects)
NEW QUESTION # 30
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
Answer: B
Explanation:
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). Reference: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 31
Given:
What is the result?
- A. Mb
MC - B. mA
- C. MA
- D. Mb
- E. Mb
Answer: B
Explanation:
The code snippet is an example of Java SE 17 code. The code is checking if the object is an instance of class C and if it is, it will print "mC". If it is not an instance of class C, it will print "mA". In this case, the object is not an instance of class C, so the output will be "mA". Reference: Pattern Matching for instanceof - Oracle Help Center
NEW QUESTION # 32
Given:
Which two method invocation execute?
- A. IFace .,4():
- B. IFace myclassobj = new Myc (); myclassObj.m3 ();
- C. IFace.m2();
- D. iFace mucloassObj = new Myc (); myClassObj.m4();
- E. Ifnce.m3 ();
- F. new MyC() .m2 ();
Answer: A,F
Explanation:
Explanation
The code given is an interface and a class that implements the interface. The interface has three methods, m1(), m2(), and m3(). The class has one method, m1(). The only two method invocations that will execute are D and E.
D is a call to the m2() method in the class, and E is a call to the m3() method in the interface. References:
https://education.oracle.com/products/trackp_OCPJSE17, 3, 4, 5
NEW QUESTION # 33
Given:
Which statement is true while the program prints GC?
- A. Only one of the objects previously referenced by t1 is eligible for garbage collection.
- B. Both the objects previously referenced by t1 are eligible for garbage collection.
- C. Only the object referenced by t2 is eligible for garbage collection.
- D. None of the objects are eligible for garbage collection.
Answer: B
NEW QUESTION # 34
Given:
Which action enables the code to compile?
- A. Replace 15 with item.display (''Flower'');
- B. Replace 3 with private static void display () {
- C. Replace 7 with public void display (string design) {
- D. Replace 2 with static string name;
Answer: C
Explanation:
Explanation
The answer is C because the code fragment contains a syntax error in line 7, where the method display is declared without any parameter type. This causes a compilation error, as Java requires the parameter type to be specified for each method parameter. To fix this error, the parameter type should be added before the parameter name, such as string design. This will enable the code to compile and run without any errors.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Java Methods
NEW QUESTION # 35
Given the code fragment:
Which code fragment invokes all callable objects in the workers set?
- A.
- B.
- C.
- D.
Answer: C
Explanation:
Explanation
The code fragment in Option C invokes all callable objects in the workers set by using the ExecutorService's invokeAll() method. This method takes a collection of Callable objects and returns a list of Future objects representing the results of the tasks. The other options are incorrect because they either use the wrong method (invokeAny() or submit()) or have syntax errors (missing parentheses or semicolons). References: AbstractExecutorService (Java SE 17 & JDK 17) - Oracle
NEW QUESTION # 36
Given:
What is the result?
- A. D D D
- B. B A D
- C. D A D
- D. B A C
Answer: B
Explanation:
Explanation
The answer is C because the code demonstrates the concept of method overloading and type conversion in Java. Method overloading allows different methods to have the same name but different parameters. Type conversion allows values of one data type to be assigned to another data type, either automatically or explicitly. In the code, the class Test has four methods named sum, each with different parameter types: int, float, and double. The main method creates an instance of Test and calls the sum method with different arguments. The compiler will choose the most specific method that matches the arguments, based on the following rules:
If there is an exact match between the argument types and the parameter types, that method is chosen.
If there is no exact match, but there is a method with compatible parameter types, that method is chosen.
Compatible types are those that can be converted from one to another automatically, such as int to long or float to double.
If there is more than one method with compatible parameter types, the most specific method is chosen.
The most specific method is the one whose parameter types are closest to the argument types in terms of size or precision.
In the code, the following method calls are made:
test.sum(10, 10.5) -> This matches the sum(int a, float b) method exactly, so it is chosen.
The result is 20.5, which is converted to int and printed as 20 (B).
test.sum(10) -> This does not match any method exactly, but it matches the sum(double a) method with compatible types, as int can be converted to double automatically. The result is 10.0, which is printed as 10
(A). test.sum(10.5, 10) -> This does not match any method exactly, but it matches two methods with compatible types: sum(float a, float b) and sum(double a, double b). The latter is more specific, as double is closer to the argument types than float. The result is 20.5, which is printed as 20 (D).
Therefore, the output is B A D. References
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Method Overloading in Java
Type conversion in Java with Examples
Java Method Overloading with automatic type conversions
NEW QUESTION # 37
Given:
What is the result?
- A. 1 RAINY
- B. 1 Snowy
- C. 0 Snowy
- D. Compilation fails
- E. 0 CLOUDY
Answer: C
Explanation:
The code is defining an enum class called Forecast with three values: SUNNY, CLOUDY, and RAINY. The toString() method is overridden to always return "SNOWY". In the main method, the ordinal value of SUNNY is printed, which is 0, followed by the value of CLOUDY converted to uppercase, which is "CLOUDY". However, since the toString() method of Forecast returns "SNOWY" regardless of the actual value, the output will be "0 SNOWY". Reference: Enum (Java SE 17 & JDK 17), Enum.EnumDesc (Java SE 17 & JDK 17)
NEW QUESTION # 38
Given the code fragment:
What is the result?
- A. $SIM6D
- B. PT5000PT60MP6D
- C. PT5SPTIMP6D
- D. 5000$60M6D
Answer: B
Explanation:
The code fragment is creating a Duration object with a value of 5000 milliseconds, then printing it. Then, it is creating another Duration object with a value of 60 seconds, then printing it. Finally, it is creating a Period object with a value of 6 days, then printing it. The output will be "PT5000PT60MP6D". Reference: https://docs.oracle.com/javase/8/docs/api/java/time/Duration.html, https://docs.oracle.com/javase/8/docs/api/java/time/Period.html
NEW QUESTION # 39
Which statement is true about migration?
- A. Every module is moved to the module path in a bottom-up migration.
- B. Every module is moved to the module path in a top-down migration.
- C. Unnamed modules are automatic modules in a top-down migration.
- D. The required modules migrate before the modules that depend on them in a top-down ^migration.
Answer: A
Explanation:
Explanation
The answer is B because a bottom-up migration is a strategy for modularizing an existing application by moving its dependencies to the module path one by one, starting from the lowest-level libraries and ending with the application itself. This way, each module can declare its dependencies on other modules using the module-info.java file, and benefit from the features of the Java Platform Module System (JPMS), such as reliable configuration, strong encapsulation, and service loading.
Option A is incorrect because a top-down migration is a strategy for modularizing an existing application by moving it to the module path first, along with its dependencies as automatic modules. Automatic modules are non-modular JAR files that are treated as modules with some limitations, such as not having a module descriptor or a fixed name. A top-down migration allows the application to use the module path without requiring all of its dependencies to be modularized first.
Option C is incorrect because a top-down migration does not require any specific order of migrating modules, as long as the application is moved first and its dependencies are moved as automatic modules. A bottom-up migration, on the other hand, requires the required modules to migrate before the modules that depend on them.
Option D is incorrect because unnamed modules are not automatic modules in any migration strategy.
Unnamed modules are modules that do not have a name or a module descriptor, such as classes loaded from the class path or dynamically generated classes. Unnamed modules have unrestricted access to all other modules, but they cannot be accessed by named modules, except through reflection with reduced security checks. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Migrating to Modules (How and When) - JavaDeploy
Java 9 Modularity: Patterns and Practices for Developing Maintainable Applications
NEW QUESTION # 40
Given the code fragment:
What is the result?
- A. true 1
false 2 - B. false 1
false 2 - C. falase 0
true 1 - D. false 1
ture 2
Answer: C
Explanation:
The code fragment is comparing the values of a, b, and c using the < and > operators. The first comparison, d, is checking if a is less than b and greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to true. The second comparison, e, is checking if a is greater than b and a is greater than c. Since a is equal to 2, b is equal to -2, and c is equal to -4, this comparison will evaluate to false. Therefore, the result will be true 1 false 2. Reference: Operators (The Java™ Tutorials > Learning the Java Language - Oracle
NEW QUESTION # 41
Given:
What is the result?
- A. Compilation fails.
- B. (Bicycle, car, motorcycle, truck)
- C. Bicycle =7, car=7, motorcycle=7, truck=7)
- D. (3:bicycle, 0:car, 0motercycle, 5:truck)
- E. Bicycle-1, car=3, motorcycle=1, truck=2)
Answer: A
Explanation:
Explanation
The answer is E because the code fragment contains several syntax errors that prevent it from compiling.
Some of the errors are:
The enum declaration is missing a semicolon after the list of constants.
The enum constants are not capitalized, which violates the Java naming convention for enums.
The switch expression is missing parentheses around the variable name.
The case labels are missing colons after the enum constants.
The default label is missing a break statement, which causes a fall-through to the next case.
The println statement is missing a closing parenthesis and a semicolon.
A possible corrected version of the code fragment is:
enum Vehicle { BICYCLE, CAR, MOTORCYCLE, TRUCK; } public class Test { public static void main(String[] args) { Vehicle v = Vehicle.BICYCLE; switch (v) { case BICYCLE: System.out.print("1"); break; case CAR: System.out.print("3"); break; case MOTORCYCLE: System.out.print("1"); break; case TRUCK: System.out.print("2"); break; default: System.out.print("0"); break; } System.out.println(); } } This would print 1 as the output. References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Enum Types
The switch Statement
NEW QUESTION # 42
......
Preparing for the 1Z0-829 exam requires a thorough understanding of the exam objectives, as well as practical experience in working with Java SE 17. Oracle provides a variety of resources to help developers prepare for the exam, including study guides, practice exams, and training courses. In addition, there are many online resources and study groups that can provide valuable support and guidance for those preparing for the exam.
Oracle 1Z0-829 certification exam is a multiple-choice exam that consists of 70 questions, and the candidate has to complete the exam within 150 minutes. 1z1-829 exam questions are designed to test the candidate's knowledge and skills in Java SE 17 and related technologies. 1z1-829 exam is available in English and Japanese languages and can be taken online or at a testing center.
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